what mass of sodium chloride will be required to completely react with 4.00 x 10(24) units of AgNO3 and form AgCl and sodium nitrate?

Answer 1

Balanced equation is:

NaCl + AgnO3 yields AgCl + NaNO3
1mol 1 mol 1 mol 1 mol

NaCl= 58.44

This is as far as I get. My answer choices are:

6.64g
0.144g
388g
8.80g

Answer 2

Here is a worked example of a stoichiometry problem. Just follow the steps. I don't think the example shows how to get to mols from molecules.
mols AgNO3 = 4E24/6.02E23 = ?
The example will take this value and go to the end. This and the limiting reagent process I gave you last yesterday will work a bunch of problems. I suggest you print them out for future reference.