Suppose that 50.0mL of 0.240M sulfric acid requires 36.0mL of KOH solution to reach its endpoint. What is the molarity of the KOH solution?

Answer 1

This works the same way as the Ba(OH)2 and HCl problem.
The equation is H2SO4 + 2KOH ==> K2SO4 = 2H2O

Answer 2

0.667