Asked by Izzy
A car traveling at 42 ft/sec decelerates at a constant 7 feet per second squared. How many feet does the car travel before coming to a complete stop?
Answers
Answered by
Damon
v = 42 - 7 t
when does v = 0?
t = 42/7
x = (1/2) a t^2
= (7/2)(42^2/49)
= 42^2/14
= 126 feet
when does v = 0?
t = 42/7
x = (1/2) a t^2
= (7/2)(42^2/49)
= 42^2/14
= 126 feet
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