Asked by rohan
an object of mass 0.5 kg is whirled at the end of string 0.8 m long if the string make three revolution in 1.2 sec find the tension of the string
Answers
Answered by
bobpursley
tension = sum of centrietal force+gravity
notice these are vectors.
tensionvertical= mg down
tensionhorizonal= m w^2 * rad
= .5*(2PI/.4)^2 * .8
now, after calculating that, you add them as vectors
tension= sqrt ( (mg)^2+(horizonalabove)^2 )
notice these are vectors.
tensionvertical= mg down
tensionhorizonal= m w^2 * rad
= .5*(2PI/.4)^2 * .8
now, after calculating that, you add them as vectors
tension= sqrt ( (mg)^2+(horizonalabove)^2 )
Answered by
sanjeet
35.6N
Answered by
Anchal
I want the nice explanation how the answer came
Answered by
Vaishnavi sharma
Good.......
Answered by
Yohannis
A force of 50 N is applied tangentially to the rim of disk 20cm in radius and mass 30kg .find the angular acceleration of the disk?
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