Asked by Anonymous
A stone dropped into water produces a circular ripple which increases in radius at a rate of 1.50 m/s. How fast is the area increasing within the ripple when its diameter is 6.00m?
Answers
Answered by
Steve
a = pir^2
da/dt = 2pi*r dr/dt
da/dt = 2pi*3 (1.5) = 9pi
da/dt = 2pi*r dr/dt
da/dt = 2pi*3 (1.5) = 9pi
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