Question
A copper pipe with an outer radius of 0.011 m runs from an outdoor wall faucet into the interior of a house. The temperature of the faucet is 4.4° C and the temperature of the pipe, at 3.1 m from the faucet, is 24° C. In fourteen minutes, the pipe conducts a total of 249 J of heat to the outdoor faucet from the house interior. Find the inner radius of the pipe. Ignore any water inside the pipe.
Answers
Assume that the body of the pipe is heat insulated and heat is conducted from one end to the other.
dQ/dt = k•A• (dT/dx),
where the heat conduction rate
dQ/dt = 249/15•60 = 0.277 J/s,
k = 390 J/s•m•oC,
the cross-sectional area of the pipe
(R and r are the outer and inner radii of the pipe)
A = π• (R^2 - r^2),
the temperature gradient
dT/dx = (24°C - 4.4°C)/3.1 = 6.32 °C/m.
Working out the equation and
you should get r = 0.0127m.
dQ/dt = k•A• (dT/dx),
where the heat conduction rate
dQ/dt = 249/15•60 = 0.277 J/s,
k = 390 J/s•m•oC,
the cross-sectional area of the pipe
(R and r are the outer and inner radii of the pipe)
A = π• (R^2 - r^2),
the temperature gradient
dT/dx = (24°C - 4.4°C)/3.1 = 6.32 °C/m.
Working out the equation and
you should get r = 0.0127m.
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