Question

What volume of hydrogen sulfide is required to produce 161 liters of sulfur dioxide according to the following reaction? (All gases are at the same temperature and pressure.)

hydrogen sulfide (g) + oxygen (g)----> water (l) + sulfur dioxide (g)
2H2S + 3O2 ==> 2H2O + 2SO2
161L SO2 x (2 mols H2S/2 mols SO2) = 161 x 2/2 = ?

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