Asked by opp
A cylinder in a car engine takes Vi = 4.50 10-2 m3 of air into the chamber at 30° C and at atmospheric pressure. The piston then compresses the air to 0.112 times of the original volume (0.112 Vi) and to 24.0 times the original pressure (24.0 Pi). What is the new temperature of the air?
Answers
Answered by
Elena
T1 =273+30 =303 K
p1•V1/T1 = p2•V2/T2
T2 = T1• p2•V2/ p1•V1=
=303•24•p1•0.112V1/ p1•V1=814.5 K
p1•V1/T1 = p2•V2/T2
T2 = T1• p2•V2/ p1•V1=
=303•24•p1•0.112V1/ p1•V1=814.5 K
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