Question

What is the invers of:

y=2log(x+1)


and please explain this to me..not just an answer.

Answer 1

What you want is an equation for x in terms of y. That will be the inverse functuon.

I will assume that the log is to base e.

y = ln (x+1)^2
e^y = (x+1)^2

x+1 = sqrt (e^y) = e^(y/2)
x = e^(y/2) - 1

Switching variables, the inverse function can be written
f^-1(x) = e^(x/2) -1

Answer 2

thanks

Answer 3

inverse of y=ln(x)+4

how would i do this?