Asked by Coach
If a car leaves a skid mark of 500 feet, how fast was the car traveling?
Using the formula r=2ã5L
Using the formula r=2ã5L
Answers
Answered by
Damon
OK, I guess
v = 2 sqrt (5 L)
v = 2 sqrt (2500)
v = 2*5*10
v = 100
v = 2 sqrt (5 L)
v = 2 sqrt (2500)
v = 2*5*10
v = 100
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