Question
find the tension in an elevator cable which must support a 4000 N elevator with a maximum upward acceleration of 2 g's. What would be the tension if the elevator were allowed to accelerate downward at .25g's?
Answers
Upwards:
-ma = mg –T1,
T1 = m(g+a).
Downwards:
ma = mg –T2,
T2 =m(g-a).
-ma = mg –T1,
T1 = m(g+a).
Downwards:
ma = mg –T2,
T2 =m(g-a).
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