Asked by Clarissa
I am still getting the wrong answrs, can you please do me a favor and for each part list the formulas and steps i need to do in order to get the answer. thank you
At serve, a tennis player aims to hit the ball horizontally.
part a)What minimum speed is required for the ball to clear the 0.90m--high net about 15.0m from the server if the ball is "launched" from a height of 2.50m ?
part b)here (relative to server) will the ball land if it just clears the net?
part c)Will it be "good" in the sense that it lands within 7.0m of the net? yes or no ?
part d) How long will it be in the air?
At serve, a tennis player aims to hit the ball horizontally.
part a)What minimum speed is required for the ball to clear the 0.90m--high net about 15.0m from the server if the ball is "launched" from a height of 2.50m ?
part b)here (relative to server) will the ball land if it just clears the net?
part c)Will it be "good" in the sense that it lands within 7.0m of the net? yes or no ?
part d) How long will it be in the air?
Answers
Answered by
Damon
I continued down below, scroll again
Do you agree on the first answer? the horizontal speed?
Do you agree on the first answer? the horizontal speed?
Answered by
Clarissa
yeah i got 26.3 because i round it off for the speed
Answered by
Damon
At serve, a tennis player aims to hit the ball horizontally.
part a)What minimum speed is required for the ball to clear the 0.90m--high net about 15.0m from the server if the ball is "launched" from a height of 2.50m ?
part b)here (relative to server) will the ball land if it just clears the net?
part c)Will it be "good" in the sense that it lands within 7.0m of the net? yes or no ?
part d) How long will it be in the air?
======================
u = 26.25 until it hits ground
how long to fall 2.5 m?
2.5 = 4.9 t^2
t =.714 second to hit ground
where will it be?
26.25 * .714 = 18.74 total horizontal dist
18.74 - 15 = 3.74 into opposite side, good shot
time in air was .714 s
part a)What minimum speed is required for the ball to clear the 0.90m--high net about 15.0m from the server if the ball is "launched" from a height of 2.50m ?
part b)here (relative to server) will the ball land if it just clears the net?
part c)Will it be "good" in the sense that it lands within 7.0m of the net? yes or no ?
part d) How long will it be in the air?
======================
u = 26.25 until it hits ground
how long to fall 2.5 m?
2.5 = 4.9 t^2
t =.714 second to hit ground
where will it be?
26.25 * .714 = 18.74 total horizontal dist
18.74 - 15 = 3.74 into opposite side, good shot
time in air was .714 s
Answered by
Clarissa
thank you, I will calculate everything again and see where I made my mistakes and compare it to these answers. Thanks alot really appreciate it
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