Asked by punk480

A circular pool with a diameter of 32 feet is surrounded by a wood deck of uniform width.

If the area of the deck is 68π square feet, what is x, the width of the deck?

Answers

Answered by Damon
x = r - 16

pi (r^2 - 16^2) = 68 pi
so
r^2 - 16^2 = 68
r^2 = 324
r = 18
x = 18-16 = 2 feet
Answered by Anonymous
2 feet
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