Question
A circular pool with a diameter of 32 feet is surrounded by a wood deck of uniform width.
If the area of the deck is 68π square feet, what is x, the width of the deck?
If the area of the deck is 68π square feet, what is x, the width of the deck?
Answers
Damon
x = r - 16
pi (r^2 - 16^2) = 68 pi
so
r^2 - 16^2 = 68
r^2 = 324
r = 18
x = 18-16 = 2 feet
pi (r^2 - 16^2) = 68 pi
so
r^2 - 16^2 = 68
r^2 = 324
r = 18
x = 18-16 = 2 feet
Anonymous
2 feet