Asked by Jane
The value of a $20,000 car decreases every, t. The equation below model this situation.
20,000(1-0.04t) = 13,000
How many years will the car be worth $13,000? Round to the nearest tenth if necessary.
I got 20,000(.96t)= 13,000, but I don't believe gives me the correct answer. Help!
20,000(1-0.04t) = 13,000
How many years will the car be worth $13,000? Round to the nearest tenth if necessary.
I got 20,000(.96t)= 13,000, but I don't believe gives me the correct answer. Help!
Answers
Answered by
Damon
this does not make sense:
" decreases every, t "
did it say it decreased 4% per year?
that would mean
.96^n =13/20
.96^n = .65
n log .96 = log .65
n = -.187/-.0177
= 10.6 years
" decreases every, t "
did it say it decreased 4% per year?
that would mean
.96^n =13/20
.96^n = .65
n log .96 = log .65
n = -.187/-.0177
= 10.6 years
Answered by
Jane
I understand most of the explanation except the part below:
n log .96 = log .65
n = -.187/-.0177
Could you please explain? Thanks
n log .96 = log .65
n = -.187/-.0177
Could you please explain? Thanks
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