Question

-√3, 3√3 Write a quadratic equation in the variable X having the given numbers as solutions. Type in standard form ax^2 + bx +c =0

Answer 1

a x ^ 2 + b x + c = a ( x - x1 ) ( x - x2 )

In this case :

x 1 = sq

Answer 2

a x ^ 2 + b x + c = a ( x - x1 ) ( x - x2 )


a leading coefficient

x1 and x2 roots


In this case :

x 1 = - sqrt ( 3)

x 2 = 3 sqrt ( 3 )


a x ^ 2 + b x + c = a [ ( x - ( - sqrt ( 3 ) ) ] * [ ( x - 3 sqrt ( 3 ) ) =

a [ ( x + sqrt ( 3 ) ) ] * [ ( x - 3 sqrt ( 3 ) ) =

a [ x * x + x * sqrt ( 3 ) - 3 sqrt ( 3 ) * x - 3 * sqrt ( 3 ) * sqrt ( 3 ) ] =

a [ x ^ 2 - 2 sqrt ( 3 ) x - 3 * 3 ] =

a [ x ^ 2 - 2 sqrt ( 3 ) x - 9 ]



a [ x ^ 2 - 2 sqrt ( 3 ) x - 9 ] = 0 Divide both sides by a

x ^ 2 - 2 sqrt ( 3 ) x - 9 = 0 / a

x ^ 2 - 2 sqrt ( 3 ) x - 9 = 0