a x ^ 2 + b x + c = a ( x - x1 ) ( x - x2 )
a leading coefficient
x1 and x2 roots
In this case :
x 1 = - 5
x 2 = -
a [ x - ( - 5 ) ] * [ x - ( - 2 ) ] =
a ( x + 5 ) * ( x + 2 ) =
a ( x * x + x * 5 + 2 * x + 2 * 5 ) =
a ( x ^ 2 + 5 x + 2 x + 10 ) =
a ( x ^ 2 + 7 x + 10 )
a ( x ^ 2 + 7 x + 10 ) = 0 Divide both sides by a
x ^ 2 + 7 x + 10 = 0 / a
x ^ 2 + 7 x + 10 = 0
Write a quadratic equation having the given numbers as solutions.
-5 and -2
The quadratic equation is: __=0
Thank you.
1 answer