Asked by CHRIS
A reaction will be nonspontaneous under all conditions when
a. delta G is negative
b. delta H is negative and DS is positive
c. delta H is positive and DS is negative
d. delta H is positive independent of the value and sign of DS
e. delta S is positive independent of the value and sign of DH
?
a. delta G is negative
b. delta H is negative and DS is positive
c. delta H is positive and DS is negative
d. delta H is positive independent of the value and sign of DS
e. delta S is positive independent of the value and sign of DH
?
Answers
Answered by
DrBob222
dG = dH - TdS.
Go through each answer and see if it fits; for example, #1 can't be right because when dG is - the reaction is spontaneous.
#2.
If dH is - and dS is +, then the term TdS is - so dG is always - when this is true and the rxn is spontaneous. So scratch 2.
Etc.
Go through each answer and see if it fits; for example, #1 can't be right because when dG is - the reaction is spontaneous.
#2.
If dH is - and dS is +, then the term TdS is - so dG is always - when this is true and the rxn is spontaneous. So scratch 2.
Etc.
Answered by
DrBob222
e is not it.
dG = dH - TdS.
If dS is + then the term -TdS will be negative but some dH values (even though they are + values) still can give a - dG value and the reaction will be spontaneous.
dG = dH - TdS.
If dS is + then the term -TdS will be negative but some dH values (even though they are + values) still can give a - dG value and the reaction will be spontaneous.
Answered by
CHRIS
so d then
Answered by
DrBob222
no. c
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