Asked by janki
                y=6-x  y=x^2
Find the area of the region by
integrating with respect to x.
Find the area of the region by integrating with respect to y.
------------------------------------
i got the intersection pts to be(-3,9)and (2,4)....i then took the integral and found the answer to be 20.8333 for both parts...HOWEVER...its wrong! please help!
            
        Find the area of the region by
integrating with respect to x.
Find the area of the region by integrating with respect to y.
------------------------------------
i got the intersection pts to be(-3,9)and (2,4)....i then took the integral and found the answer to be 20.8333 for both parts...HOWEVER...its wrong! please help!
Answers
                    Answered by
            Reiny
            
    Your intersection points are correct
Method1:
the effective height of a slice = 6-x - x^2
area = ∫ (6-x - x^2) dx from x = -3 to 2
= [6x - x^2/2 - x^3/3] from -3 to 2
= 12 - 2 - 8/3 - (-18 -9/2 - (-27/3) )
= 10 - 8/3 + 9 + 9/2
= 19 + 11/6
= 20 5/6 or 125/6 , so you were right
    
Method1:
the effective height of a slice = 6-x - x^2
area = ∫ (6-x - x^2) dx from x = -3 to 2
= [6x - x^2/2 - x^3/3] from -3 to 2
= 12 - 2 - 8/3 - (-18 -9/2 - (-27/3) )
= 10 - 8/3 + 9 + 9/2
= 19 + 11/6
= 20 5/6 or 125/6 , so you were right
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