a bar is pushed so that it slides across the floor. how far will it go, given the coefficient of kinetic friction is 0.25, and the push imparts an initial speed of 2.5m/s?

Answer 1

stopping force = -.25 * m * 9.8
F = m a
a = -.25 * 9.8 = -2.45 m/s^2

v = 2.5 - 2.45 t
so stops at t = 1.02 seconds
x = 2.5 * 1.02 + (1/2)(-2.45) (1.02)^2
x = 2.55 - 1.27 = 1.28 m