Asked by Julie
Determine the derivative of each function
A1) y = e^x(Sin²x)
A2) y = e²Sin²x
B1) y = (x³ + 1)e^-2
B2) y = (x² + 1)e^-2
C) y = x²(theta^Sinx)
A1) y = e^x(Sin²x)
A2) y = e²Sin²x
B1) y = (x³ + 1)e^-2
B2) y = (x² + 1)e^-2
C) y = x²(theta^Sinx)
Answers
Answered by
Damon
I am not going to do all these
if y = u(x) v(x)
then dy/dx = u dv/dx + v du/dx
for A1
u = e^x so du/dx = e^x
v = sin^2 x so dv/dx = 2 sin x cos x
so
dy/dx = 2e^x sin x cos x + e^x sin^2 x
= e^x sin x ( 2 cos x + sin x)
if y = u(x) v(x)
then dy/dx = u dv/dx + v du/dx
for A1
u = e^x so du/dx = e^x
v = sin^2 x so dv/dx = 2 sin x cos x
so
dy/dx = 2e^x sin x cos x + e^x sin^2 x
= e^x sin x ( 2 cos x + sin x)
Answered by
Julie
Could you help me for these two:
b) y = (x²+1)e^-4
c) y = x²(e^Sinx)
Please & Thank you.
b) y = (x²+1)e^-4
c) y = x²(e^Sinx)
Please & Thank you.
Answered by
Damon
e^-4 is a constant
so
e^-4(2x)
x^2 d/dx (e^sin x) + 2 x e^sin x
x^2 (e^sin x)cos x + 2 x e^sin x
x e^sin x [ x cos x + 2 ]
so
e^-4(2x)
x^2 d/dx (e^sin x) + 2 x e^sin x
x^2 (e^sin x)cos x + 2 x e^sin x
x e^sin x [ x cos x + 2 ]
Answered by
Julie
The answer for b) is e^-4(2x) ?
And everything after that is for c) right. So the final answer for c) would be xe^sinx(xcosx + 2)
?
Thankyou.
And everything after that is for c) right. So the final answer for c) would be xe^sinx(xcosx + 2)
?
Thankyou.
Answered by
Julie
In part c) for xcosx could you simplify that or do you keep it as xcosx? Thanks
There are no AI answers yet. The ability to request AI answers is coming soon!