First, find where they intersect.
4x+y^2=9, x=2y
4(2y) + y^2 = 9
y^2 + 8y - 9 = 0
(y+9)(y-1) = 0
So, it might be easier to integrate in the y-direction:
∫[-9,1] (y^2-9)/4 - 2y dy
∫[-9,1] y^2/4 - 2y - 9/4 dy
y^3/12 - y^2 - 9/4 y [-9,1]
(-729/12 - 81 + 81/4) - (1/12 - 1 - 9/4)
355/3
Find the area of the region enclosed by the given curves:
4x+y^2=9, x=2y
3 answers
Unfortunately, that answer is not right...
This is the last problem on my homework and I've been stuck on it for about an hour. Its very frustrating
This is the last problem on my homework and I've been stuck on it for about an hour. Its very frustrating
How about 125/3 ?
If you had read my posting carefully (as I did not) you'd have noticed that it should have been
(9-y^2)/4
If you had read my posting carefully (as I did not) you'd have noticed that it should have been
(9-y^2)/4