Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Electronic types neglect the force of gravity on electrons.To see why, compute the force of Earth's gravity on an electron and...Asked by Kristie
Electronic types neglect the force of gravity on electrons.To see why, compute the force of Earth's gravity on an electron and compare it with the force exerted on the electron by an electric field of magnitude 6000 V/m (a relatively small field). The mass of an electron is 9.1 * 10-31 kg and the charge of an electron is 1.6 * 10-19
I came up with 5.7*10^-12 and it marked me wrong.....HELP!!
I came up with 5.7*10^-12 and it marked me wrong.....HELP!!
Answers
Answered by
bobpursley
I can vouch it is probably wrong...
force electric= Eq= 6000*1.6E-19=9.6E-16M
force gravity= GMe m/re^2=9.8N/kg * 9.1E-31kg=8.9E-30 N
Now the ratio of Fgravaity/Felectric=
= 8.9E-30/8.9E-3=1E-27 which is significantly different than yours. Recheck your and my work.
force electric= Eq= 6000*1.6E-19=9.6E-16M
force gravity= GMe m/re^2=9.8N/kg * 9.1E-31kg=8.9E-30 N
Now the ratio of Fgravaity/Felectric=
= 8.9E-30/8.9E-3=1E-27 which is significantly different than yours. Recheck your and my work.
Answered by
Kristie
GOT IT THANKS ..FINALLY
1.1*10^14
1.1*10^14
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.