Asked by Josh
Evaluate the expression under the given conditions.
tan(A+B); cosA=-1/7, A in quadrant 3, sinB=1/2, B in quadrant 2.
tan(A+B); cosA=-1/7, A in quadrant 3, sinB=1/2, B in quadrant 2.
Answers
Answered by
Steve
in Q3, tan is positive, so tanA = √48
in Q2, tan is negative, so tanB = -1/√3
Now apply the addition formula
tan(A+B) = (tanA+tanB)/(1-tanA tanB)
in Q2, tan is negative, so tanB = -1/√3
Now apply the addition formula
tan(A+B) = (tanA+tanB)/(1-tanA tanB)
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