Asked by sandra

10.2
can someone show me this graph(x+2)^2/4+(y+2)^2/15=1
Answered by Steve
wolframalpha . com can. Just enter

plot (x+2)^2/4+(y+2)^2/15=1

Hyperbola with center at (-2,-2), eccentricity = √15/2
Answered by Steve
oops
ellipse, semi-major axes 2 and √15
major axis parallel to y-axis
Answered by sandra
thank you
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