Asked by Lisa
Can you show us how to use law of cosines to show that theta equals inverse cosine of (a^2 + b^2 -484)/(2ab) where a^2=(7+xcos a)^2 + (28-xsin a)^2 and b^2=(7+xcos a)^2 + (xsin a -6)^2? Thanks
Answers
Answered by
Reiny
Lisa, saw that one last night,
confused about the angle 'a'
in xcosa and xsina.
secondly where does x come in ?
describe your triangle.
I have a triangle with sides a and b and Ø as its contained angle.
confused about the angle 'a'
in xcosa and xsina.
secondly where does x come in ?
describe your triangle.
I have a triangle with sides a and b and Ø as its contained angle.
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