Asked by Clare

(100x^3y^-2)/(64x^7y^4)
Answered by Clare
Please simplify completely :)
Answered by Reiny
100/64 = 25/16

x^3 / x^7 = 1/x^4

y^-2 / y^4 = 1/y^6

so (100x^3y^-2)/(64x^7y^4)
=25/(16 x^4 y^6)
Answered by Clare
wait isn't (y^-2)/(y^4)=y^2?
Answered by Reiny
nope

(y^-2) times y^4 would be y^2, but you were dividing, so you have to subtract the exponents
-2 - 4 = -6
Answered by Clare
Ohh right thank you
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