Asked by Brea
Calculate the volume of 1.78M sulfuric acid that would be needed to neutralize 62.4 mL of a 2.09 M aqueous ammonia solution. The equation for the reaction is
H2SO4(aq) + 2 NH3(aq) ---> 2 NH4(aq)+ SO4
^-2 (aq)
H2SO4(aq) + 2 NH3(aq) ---> 2 NH4(aq)+ SO4
^-2 (aq)
Answers
Answered by
DrBob222
How much NH3 do you have? That is mols = M x L = ?
Look at the coefficients in the balanced equation. It takes 1/2 as much H2SO4. So mols H2SO4 = 1/2 mols NH3.
M H2SO4 = mols H2SO4/L H2SO4.
You know M and mols, solve for L.
Look at the coefficients in the balanced equation. It takes 1/2 as much H2SO4. So mols H2SO4 = 1/2 mols NH3.
M H2SO4 = mols H2SO4/L H2SO4.
You know M and mols, solve for L.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.