Asked by janet
two fair dice are rolled, find the
A)odds of getting a 9
B) the odds against getting a 12
A)odds of getting a 9
B) the odds against getting a 12
Answers
Answered by
bobpursley
you can get it with a 5,4; 6,3
pr= 2*pr(5,4)+ 2*pr(6,3)= 4*1/6*1/6=1/9
against a 12, that is the same as 1-pr(12)
pr= 1-1/6*1/6= 35/36
pr= 2*pr(5,4)+ 2*pr(6,3)= 4*1/6*1/6=1/9
against a 12, that is the same as 1-pr(12)
pr= 1-1/6*1/6= 35/36
Answered by
idk
23
Answered by
norbu
If you roll a fair-sided die twice, what is the probability of getting a double?
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