Asked by Anonymous
This is second part is built off the first question. These are all from a practice test.
How much heat is required to raise the temperature of exactly one liter of water fro m 60 °F to 180 °F?
correct answer: 279kj
How much alcohol must be burned to generate enough heat to warm the water as described in problem 3?
correct answer: 10.4
the only mention of an alcohol is ethyl alcohol (C2H6O) in the question before this where you find its heat of combustion.
correct answer: -1238.43 kJ/mol
How much heat is required to raise the temperature of exactly one liter of water fro m 60 °F to 180 °F?
correct answer: 279kj
How much alcohol must be burned to generate enough heat to warm the water as described in problem 3?
correct answer: 10.4
the only mention of an alcohol is ethyl alcohol (C2H6O) in the question before this where you find its heat of combustion.
correct answer: -1238.43 kJ/mol
Answers
Answered by
DrBob222
60F is 15.55 C
180 F is 82.22C
delta T = 82.22-15.55 = 66.67
q = mass x specific heat x delta T
q = 100g x 4.184 x 66.67
q = 278,947 = 279 kJ.
Burning alcohol (46 g ethanol) provides 1238.43 kJ/mol. We want to know how many g ethanol to burn to provide 279 kJ.
46 g x (279/1238.43) = 10.36 g which rounds to 10.4 g.
180 F is 82.22C
delta T = 82.22-15.55 = 66.67
q = mass x specific heat x delta T
q = 100g x 4.184 x 66.67
q = 278,947 = 279 kJ.
Burning alcohol (46 g ethanol) provides 1238.43 kJ/mol. We want to know how many g ethanol to burn to provide 279 kJ.
46 g x (279/1238.43) = 10.36 g which rounds to 10.4 g.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.