Question

The solvay process in an industrial method for preparing baking soda. In the process, CO2, NH3, H2O, and NaCl react to produce NaHCO3. If 25.0 L of carbon dioxide gas at STP and 20.0 L of ammonia gas at STP react in excess water and salt, what is the mass of baking soda produced ? The equation for the reaction is: CO2 (g) + NH3(g)+H2O(l)+NaCl(s)= NaHCO3(s)+NH4Cl(aq)

Answer 1

CO2 x (1 mol/22.4L) = 1.12 mols CO2.
NH3 x (1 mol/22.4L) = 0.89 mols NH3.
Therefore, NH3 is the limiting reagent and you will produce 0.89 mol NaHCO3. Convert that to grams.

Answer 2

0.89 mol NaHCO3* 84.01g = 74.8 g ?

Answer 3

For the following reaction, 0.431 moles of iron are mixed with 0.293 moles of oxygen gas.

iron (s) + oxygen (g) iron(II) oxide (s)

What is the FORMULA for the limiting reagent

Answer 4

75.0 g NaHCO3