Asked by Liz
Please help!!
Differentiate:
y=(x^2-1)^(1/2)/x^2
Differentiate:
y=(x^2-1)^(1/2)/x^2
Answers
Answered by
####Nadine####
Chain and quotient rule
((1/2)(2x)(x^2-1)^-1/2)x^2 -2x(x^2-1)^1/2)/x^4
simplifies to
(x^3(x^2-1)^-1/2 -2x(x^2-1)^1/2)/x^4
simplifies to
(x^2-1)^-1/2(x^2)-2(x^2-1))/x^3
final answer
((x^2-1)^(-1/2))(-x^2+2)/x^3
((1/2)(2x)(x^2-1)^-1/2)x^2 -2x(x^2-1)^1/2)/x^4
simplifies to
(x^3(x^2-1)^-1/2 -2x(x^2-1)^1/2)/x^4
simplifies to
(x^2-1)^-1/2(x^2)-2(x^2-1))/x^3
final answer
((x^2-1)^(-1/2))(-x^2+2)/x^3