Asked by JACK
In putting, the force with which a golfer strikes a ball is planned so that the ball will stop within some small distance of the cup, say 2.00m long or short, in case the putt is missed. Accomplishing this from an uphill lie (that is, putting the ball downhill, ) is more difficult than from a downhill lie.
part a)To see why, assume that on a particular green the ball decelerates constantly at 1.6m/s^2 going downhill, and constantly at 2.5m/s^2 going uphill. Suppose we have an uphill lie 7.0m from the cup. Calculate the allowable range of initial velocities we may impart to the ball so that it stops in the range 2.00m short to 2.00m long of the cup.
part b)Do the same for a downhill lie 7.0m from the cup.
part a)To see why, assume that on a particular green the ball decelerates constantly at 1.6m/s^2 going downhill, and constantly at 2.5m/s^2 going uphill. Suppose we have an uphill lie 7.0m from the cup. Calculate the allowable range of initial velocities we may impart to the ball so that it stops in the range 2.00m short to 2.00m long of the cup.
part b)Do the same for a downhill lie 7.0m from the cup.
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