Asked by Lina
A steel beam is used in the construction of a skyscraper. By what fraction (change in L)/(Lo) does the length of the beam increase when the temperature changes from that on a cold winter day (-15 F) to that on a summer day (+105 F)?
Can anyone please give me some hints to do it?THANKS A LOT!
Can anyone please give me some hints to do it?THANKS A LOT!
Answers
Answered by
DrBob222
http://en.wikipedia.org/wiki/Coefficient_of_thermal_expansion
Answered by
Lina
but i got .00144 for the answer...
the correct answer should be 8.0*10^-4
how come?
the correct answer should be 8.0*10^-4
how come?
Answered by
Kelly
T= ((105-32)*5/9)-((-15-32)*5/9)
= 40.55-(-26.11)
= 66.66
L/Lo = (12*10^-6)(66.66)
= 8.00*10^-4
= .0008
= 40.55-(-26.11)
= 66.66
L/Lo = (12*10^-6)(66.66)
= 8.00*10^-4
= .0008
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