Asked by lindsay
the fundamental theorem of calculus,
f(x)=∫(0,x) t^3+2t^2+2dt, and find f"(x).
my answer was:
f'(x)=x^3+x^2+2
f"(x)=x^4/4 + 2x^3/3 + 2x
it said its wrong.
f(x)=∫(0,x) t^3+2t^2+2dt, and find f"(x).
my answer was:
f'(x)=x^3+x^2+2
f"(x)=x^4/4 + 2x^3/3 + 2x
it said its wrong.
Answers
Answered by
Steve
well, yeah.
f'' = 3x^2 + 2x
why did you take the antiderivative to go from f' to f''?
f'' = 3x^2 + 2x
why did you take the antiderivative to go from f' to f''?
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