Question

If a student starts with 0.387 g of p-anisaldehyde and ends up with 0.265 g of methyl-E-4-methoxycinnamate, what are their theoretical and percent yields?

Answers

DrBob222
1. Write the equation. It isn't necessary to balance everything but you must know how many mols of the prouct you obtain for 1 mol of the reactant.
2. Convert 0.387g to mols. mols = grams/molar mass.
3. Using the coefficients in the balanced equation, convert mols of the reactant to mols of the product.
4. Convert g to mols. g = mols x molar mass. This is the theoretical yield of the methyl E compound.
5. %yield = (actual grams yield/theoreticl yield)*100 = ?
Lor
Thanks! However, Do I convert the g I got by dividing by the molar mass of methyl E? The reaction is 1-to-1.
DrBob222
As I outlined it, you convert the para compd to mols. If the rxn is 1:1, you will get that many mols of the methyl E cmpd. Convert that to grams as I wrote; g = mols methyl E x molar mass. That is the theoretical yield of the methyl E.
Then %yield = (0.265 methyl E/theoretical yield of methyl E)*100 = ?
Lor
Thank you so much!!! :)
Sam
78

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