A 100 mL sample of 0.10M HCl is mixed with 50mL of 0.10M NH3 (Kb=1.8x10^-5). What is the resulting pH?

Answer 1

mols HCl = M x L = ?
mols NH3 = M x L = ?
Subtract mols HCl-mols NH3,
then pH = -log(H^+)

Answer 2

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