easy. think on Newton.
Fg= GMe*M/distance^2
distance= re+670km
A simpler method to do this
Fg= 2160*9.8 (re/(re+670))^2
A satellite used in a cellular telephone network has a mass of 2160 kg and is in a circular orbit at a height of 670 km above the surface of the earth.
What is the gravitational force Fgrav on the satellite?
Take the gravitational constant to be = 6.67×10−11 N*m^2/kg^2, the mass of the earth to be = 5.97×1024 kg, and the radius of the Earth to be = 6.38×106 m.
Express your answer in newtons.
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