Question

A satellite used in a cellular telephone network has a mass of 2160 kg and is in a circular orbit at a height of 670 km above the surface of the earth.

What is the gravitational force Fgrav on the satellite?

Take the gravitational constant to be = 6.67×10−11 N*m^2/kg^2, the mass of the earth to be = 5.97×1024 kg, and the radius of the Earth to be = 6.38×106 m.

Express your answer in newtons.

Answer 1

easy. think on Newton.

Fg= GMe*M/distance^2

distance= re+670km

A simpler method to do this

Fg= 2160*9.8 (re/(re+670))^2