a total of 8 meters of fencing are going to be used to fence in a rectangular cage for pets and divide it into three smaller cages

Question

**the photo that is shown with this question is three (3) boxes stuck together side by side horizontally***

determine the overall dimensions that will yield the maximum total enclosed area.

Answer 1

Let p=Length; n =width
8=2n+4p;
p=2-n/2

Area=np =n(2-n/2)=2n-(n^2)/2
Derivative:2-n
Critical value: 2-n=0
n=2

P=2-2/2=1
1meter by 2 meter