Asked by Cheril

Select the equation that solves this problem:
Eight coins (dimes and quarters) are worth 170 cents. How many dimes are
there?
a. 10d + 25(11 - d) = 170
b. 10d + 25(8 - d) = 170
c. 10d + 5(8 - d) = 60
d. 10d + 5(11 - d) = 60
Answered by bobpursley
So what do you think?
Answered by Bosnian
I send to you solution for simmilar problem.
Answered by Bosnian
A quarters is worth 25 cents and a dime is worth 10 cents.


q = numbers of a quarters

d = numbers of a dimes


q + d = 8

q = 8 - d


Value of money :

10 ¢ * d + 25 ¢ * q = 170 ¢

10 d + 25 q = 170

10 d + 25 ( 8 - d ) = 170


Equation b.


10 d + 25 ( 8 - d ) = 170

10 d + 25 * 8 + 25 * ( - d ) = 170

10 d + 200 - 25 d = 170

10 d - 25 d = 170 - 200

- 15 d = - 30 Divide both sides by - 15

d = - 30 / - 15

d = 2


q = 8 - d = 8 - 2 = 6


2 dimes and 6 quarters


2 * 10 ¢ + 6 * 25 ¢ =

20 ¢ + 150 ¢ = 170 ¢