Question

At a certain temperature the vapor pressure of pure benzene is measured to be 322. torr . Suppose a solution is prepared by mixing 138.g of benzene and 91.2g of heptane .

Calculate the partial pressure of benzene vapor above this solution. 3 sig figs!

Steps/equations are appreciated...!
n benzene = grams/molar mass
n heptane = grams/molar mass
Xbenzene = n benzene/totalmols

pbenzene = Xbenzene*P<sup>o</sup><sub>benzene</sub>
llama

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