Question

if you tossed two number cubes, what sum has the greatest probability of occuring? Explain.

Answer 1

a sum of 7 has a prob of 6/36 = 1/6
to get a 7:
16, 25, 34, 43, 52, 61 ----> 6 of them

all other sums have a lesser count
e.g.
to get a 5:
14, 23, 32, 41, --- only 4 of them

Answer 2

well this is no help at all so take this website down now

Answer 3

Look at the list. 7 is in all of the lists, so 7 is the answer.
1,1=2
1,2=3
1,3=4
1,4=5
1,5=6
1,6=7
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2,1=3
2,2=4
2,3=5
2,4=6
2,5=7
2,6=8
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3,1=4
3,2=5
3,3=6
3,4=7
3,5=8
3,6=9
-----------------------------------------
4,1=5
4,2=6
4,3=7
4,4=8
4,5=9
4,6=10
-----------------------------------------
5,1=6
5,2=7
5,3=8
5,4=9
5,5=10
5,6=11
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6,1=7
6,2=8
6,3=9
6,4=10
6,5=11
6,6=12

Answer 4

7 because it is the number which is the nearest number to the middle.
(0.5 meant add 1)

Answer 5

That's correct! Another way to explain it is that there are 6 different ways to get a sum of 7 when tossing two number cubes (1+6, 2+5, 3+4, 4+3, 5+2, 6+1), which is more than any other possible sum. Therefore, the sum of 7 has the greatest probability of occurring.