Asked by Anonymous
a standard deck of playing cards contaons 52 cards in for suits of 13 cards each. two suits are red and two suits are black. find each probability. assume the first card is replaced before the second is drawn.
(balck,Queen) (black,Diamond) (jack,Queen)
(balck,Queen) (black,Diamond) (jack,Queen)
Answers
Answered by
Reiny
first one:
prob(black) = 1/2
prob(queen) = 4/52 = 1/13
prob(black queen in that order) = (1/2)(1/13) = 1/26
There are several interpretations possible for this question.
e.g.
- what if you first card is the black queen? can the second card be anything?
- does the order matter, that is, do you consider (black, queen) the same as (queen, black) ?
etc.
prob(black) = 1/2
prob(queen) = 4/52 = 1/13
prob(black queen in that order) = (1/2)(1/13) = 1/26
There are several interpretations possible for this question.
e.g.
- what if you first card is the black queen? can the second card be anything?
- does the order matter, that is, do you consider (black, queen) the same as (queen, black) ?
etc.