Asked by Kelsey
                I need help ASAP! 
Colligative Properties-
Ethylene glycol (C2H6O2) is the principal ingredient in antifreeze. How many grams of ethylene glycol will be needed to lower the freezing point of 2100 grams of water by 20 degrees celcius?
            
            
        Colligative Properties-
Ethylene glycol (C2H6O2) is the principal ingredient in antifreeze. How many grams of ethylene glycol will be needed to lower the freezing point of 2100 grams of water by 20 degrees celcius?
Answers
                    Answered by
            DrBob222
            
    delta T = Kf*m
Solve for m = molality
m = mols/kg solvent
You have m and kg solvent; solve for mols.
mols = grams/molar mass
You have mol and molar mass, solve for grams.
Note the correct spelling of celsius.
    
Solve for m = molality
m = mols/kg solvent
You have m and kg solvent; solve for mols.
mols = grams/molar mass
You have mol and molar mass, solve for grams.
Note the correct spelling of celsius.
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