Asked by Kelsey
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Colligative Properties-
Ethylene glycol (C2H6O2) is the principal ingredient in antifreeze. How many grams of ethylene glycol will be needed to lower the freezing point of 2100 grams of water by 20 degrees celcius?
Colligative Properties-
Ethylene glycol (C2H6O2) is the principal ingredient in antifreeze. How many grams of ethylene glycol will be needed to lower the freezing point of 2100 grams of water by 20 degrees celcius?
Answers
Answered by
DrBob222
delta T = Kf*m
Solve for m = molality
m = mols/kg solvent
You have m and kg solvent; solve for mols.
mols = grams/molar mass
You have mol and molar mass, solve for grams.
Note the correct spelling of celsius.
Solve for m = molality
m = mols/kg solvent
You have m and kg solvent; solve for mols.
mols = grams/molar mass
You have mol and molar mass, solve for grams.
Note the correct spelling of celsius.
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