Ask a New Question

Asked by Randy

$$ x = \dfrac{1}{{\color{red}2}} y^2 $$
13 years ago

Answers

Answered by PsyDAG
What is your question?
13 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

{\dfrac{2}{5}k-\dfrac{3}5+\dfrac{1}{10}k} \[ -\dfrac{5}{7} \times \dfrac{1}{5} \] Let $f(x) = \dfrac{2-3x}{5-2x}$. For what value of $a$ is $f(a) = 3$? Let $f(x) = \dfrac{2-3x}{5-2x}$. For what value of $a$ is $f(a) = 3$? Thanks! If \dfrac{x-1}{3}=k 3 x−1 ​ =kstart fraction, x, minus, 1, divided by, 3, end fraction, equals... \[\dfrac{-2}{3} \div 2\dfrac{1}{4} = \] Solve for \[x\]. \[\dfrac{11^{x}}{11^3}=11^2\] \[\dfrac{2}{-3} \div \left(-1\dfrac{2}{7}\right) = \] \[1\dfrac{2}{7} \div \left(-2\dfrac{1}{4}\right) = \] \[ -\dfrac{6}{7} \times \left(-\dfrac{5}{4}\right) \]
Submit Your Answer

Question

$$ x = \dfrac{1}{{\color{red}2}} y^2 $$

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use