Which is true for the graph of x^2-9/x^2-4
the answer is vertical asymptotes at x = ±2 but i don't understand why.
3 answers
look at the denominator. What happens to a function which has a zero in the denominator?
i don't understand what you mean
consider y = 1/x
division by zero is not defined. The closer x gets to 0, the larger y gets. At x=0, y is undefined, infinitely large.
Same for this problem. What happens to y as x gets close to 2? x^2-4 gets close to 0, and you cannot divide by 0.
division by zero is not defined. The closer x gets to 0, the larger y gets. At x=0, y is undefined, infinitely large.
Same for this problem. What happens to y as x gets close to 2? x^2-4 gets close to 0, and you cannot divide by 0.
0 answers