Asked by Angel
A double-slit interference experiment is performed with light from a laser. The separation between the slits is 0.58 mm, and the
first-order maximum of the interference pattern is at an angle of 0.060
◦
from the center of
the pattern.
What is the wavelength of the laser light?
Answer in units of nm
first-order maximum of the interference pattern is at an angle of 0.060
◦
from the center of
the pattern.
What is the wavelength of the laser light?
Answer in units of nm
Answers
Answered by
Elena
The coordinate of the maximum is
x(max) = k•λ•L/d,
for the first max k=1
x(max1) = λ•L/d,
tanα = x(max1)/L = λ/d.
λ = d• tanα = 0.55•10^-3•1.047•10^-3 = 5.76•10^-7 = 576 nm
x(max) = k•λ•L/d,
for the first max k=1
x(max1) = λ•L/d,
tanα = x(max1)/L = λ/d.
λ = d• tanα = 0.55•10^-3•1.047•10^-3 = 5.76•10^-7 = 576 nm
Answered by
Angel
Excuse me what was the equation you used? Because the answer is wrong.
Answered by
Angel
And where did you get those numbers?
Answered by
Elena
I've taken 0.55 mm instead of 0.58 mm
If d = 0.55•10^-3, and tan α =1.047•10^-3,
λ = d• tanα = 0.58•10^-3•1.047•10^-3 = 6.07•10^-7 = 607 nm.
If d = 0.55•10^-3, and tan α =1.047•10^-3,
λ = d• tanα = 0.58•10^-3•1.047•10^-3 = 6.07•10^-7 = 607 nm.
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