Question
A double-slit interference experiment is performed with light from a laser. The separation between the slits is 0.58 mm, and the
first-order maximum of the interference pattern is at an angle of 0.060
◦
from the center of
the pattern.
What is the wavelength of the laser light?
Answer in units of nm
first-order maximum of the interference pattern is at an angle of 0.060
◦
from the center of
the pattern.
What is the wavelength of the laser light?
Answer in units of nm
Answers
The coordinate of the maximum is
x(max) = k•λ•L/d,
for the first max k=1
x(max1) = λ•L/d,
tanα = x(max1)/L = λ/d.
λ = d• tanα = 0.55•10^-3•1.047•10^-3 = 5.76•10^-7 = 576 nm
x(max) = k•λ•L/d,
for the first max k=1
x(max1) = λ•L/d,
tanα = x(max1)/L = λ/d.
λ = d• tanα = 0.55•10^-3•1.047•10^-3 = 5.76•10^-7 = 576 nm
Excuse me what was the equation you used? Because the answer is wrong.
And where did you get those numbers?
I've taken 0.55 mm instead of 0.58 mm
If d = 0.55•10^-3, and tan α =1.047•10^-3,
λ = d• tanα = 0.58•10^-3•1.047•10^-3 = 6.07•10^-7 = 607 nm.
If d = 0.55•10^-3, and tan α =1.047•10^-3,
λ = d• tanα = 0.58•10^-3•1.047•10^-3 = 6.07•10^-7 = 607 nm.
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