Asked by Cassie
A professional baseball diamond is a square. The distance from base to base is 90 ft. To the nearest foot, how far does a catcher standing at home plate throw the ball across the diagonal of the square to second base?
Answers
Answered by
Reiny
D^2 = 90^2 + 90^2
= 8100+8100
= 16200
D =√16200 = 127 ft , to the nearest foot
= 8100+8100
= 16200
D =√16200 = 127 ft , to the nearest foot
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