Asked by carla
calculate the volume of a 0.02M mno4- solution that is required to react completely with 10.0ml of 0.1M c2o4-2
Answers
Answered by
DrBob222
Write the equation and balance it.
mols C2O4^2- = M x L = ?
Using the coefficients in the balanced equation, convert mols oxalate to mols permanganate. Then
M MnO4^- = mols/L. You know M and mols, solve for L.
mols C2O4^2- = M x L = ?
Using the coefficients in the balanced equation, convert mols oxalate to mols permanganate. Then
M MnO4^- = mols/L. You know M and mols, solve for L.
Answered by
carla
molarity times liters? but where would i get liters from?
Answered by
DrBob222
Read the problem.
mols oxalate = M x L
M = 0.1M
volume = 10.0mL = 0.010 L big as life right there in the problem.
mols oxalate = M x L
M = 0.1M
volume = 10.0mL = 0.010 L big as life right there in the problem.
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