Asked by Miriam
A man (mass = 78.6 kg) is jogging through the woods and runs straight into a large oak tree at 6.1 m/s. Rebound speed is measured at 5.2 m/s in the opposite direction. If the time of contact with the tree is 0.041s, what is the magnitude of the force that the tree exerts on the man?
Answers
Answered by
Elena
F•Δt = Δ(m•v) = m• Δv= m(v2-v1),
F = m(v2-v1)/Δt = 78.6(6.1 – (-5.2))/0.041= 21663 N
F = m(v2-v1)/Δt = 78.6(6.1 – (-5.2))/0.041= 21663 N
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