Question

A proton is located at a distance of 0.430 m from a point charge of +8.30 µC. The repulsive electric force moves the proton until it is at a distance of 1.55 m from the charge. Suppose that the electric potential energy lost by the system is carried off by a photon that is emitted during the process. What is its wavelength?
ΔPE = PE1 – PE2 = k•q•e•(1/r1 – 1/r2) =
=9•10^9•8.3•10^-6•1.6•10^-19•(1/0.43 – 1/1.55) =
=2.01•10^-14 J.
Energy of photon
E= h•c/λ,
where h is Planck constant, c is the speed of light.
λ = h•c/E = 6.626•10^-34•3•10^8/2.01•10^-14 =9.8•10^-12 m

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